2015/10/20
SICP 問題 2.28
(define x (list (list 1 2) (list 3 4)))
(define (fringe l)
(cond ((null? l) nil)
((pair? (car l)) (append (fringe (car l))
(fringe (cdr l))))
(else (cons (car l) (fringe (cdr l))))))
gosh> (fringe x)
(1 2 3 4)
gosh> (fringe (list x x))
(1 2 3 4 1 2 3 4)